3x+4=100x^2

Solution for 3x+4=100x^2 equation:

3x+4=100x^2

We move all terms to the left:

3x+4-(100x^2)=0

determiningTheFunctionDomain
-100x^2+3x+4=0

a = -100; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-100)·4
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1609}}{2*-100}=\frac{-3-\sqrt{1609}}{-200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1609}}{2*-100}=\frac{-3+\sqrt{1609}}{-200}
$